Welcome to the Statistics Chapter Mock Test for Class 9 Mathematics, designed as per the latest NCERT and CBSE syllabus.
This test gives students the perfect opportunity to revise, practice, and evaluate their understanding of data handling, frequency distribution, mean, median, and mode.

The mock test provides a mix of conceptual and numerical questions that will help you master this essential topic and prepare effectively for your unit tests, half-yearly exams, and board exams.

1. Mode of the data 4, 6, 9, 6, 4, 2, 4, 8, 6, 4, 3, 4, 6 is

 
 
 
 

2. For a Mathematics test given to 15 students, the following marks (out of 100) are recorded : 41, 39, 48, 52, 46, 62, 54, 40, 96, 52, 98, 40, 42, 52, 60

The mean, median and mode of this data are :

 
 
 
 

3. If each observation of the data is increased by 5, then their mean

 
 
 
 

4. Median of the distribution 5, 9, 8, 6, 3, 5, 7, 12, 15 is

 
 
 
 

5. A data is such that its minimum value is 86 and range is 32, then the maximum value is

 
 
 
 

6. In a company, we need to find the central value of salaries of employees in all categories, i.e. I, II, III, IV, then we must find

 
 
 

7. In a frequency distribution, the mid-value of a class is 10 and the width of the class is 6. The lower limit of the class is

 
 
 
 

8. In histogram also we use bars and values. How it is different from bar graph ?

 
 
 

9. The maximum value of the data is 57 and range is 20, then the minimum value is

 
 
 
 

10. One day, I decided to sit in a shoe shop and observe. I noticed that out of shoes numbers 6, 7, 8 or 9, there were maximum sale for shoe number 8. Which measure of central tendency gives the average?

 
 
 

11. Direction: In the following questions, a statement of assertion (A) is followed by a statement of reason (R) is given. Choose the correct answer out of the following choices.

Assertion (A): In bar Graph, the width of the bar is not important.
Reason (R): We take equal width for all bars and maintain equal gaps in between for the sake of clarity.

 
 
 
 

12. Mean of 20 observations is 17. If 25 is subtracted from the sum of observations, then remaining sum is

 
 
 
 

13. Given the class intervals 1 – 10, 11 – 20, 21 – 30, …,  then 20 is considered in class

 
 
 
 

14. Mean of 20 observations is 15.5. Later, it was found that the observation 24 was misread as 42. The corrected mean is :

 
 
 
 

15. Direction: In the following questions, a statement of assertion (A) is followed by a statement of reason (R) is given. Choose the correct answer out of the following choices.

Assertion (A): One cannot be drawn frequency polygon curve without plotting a Histogram.
Reason (R): Assertion is false but Reason is true because frequency polygon can also be drawn by using the class mark.

 
 
 
 

16. Direction: In the following questions, a statement of assertion (A) is followed by a statement of reason (R) is given. Choose the correct answer out of the following choices.

Assertion (A): The mid pointof the class interval is equal to the average of upper limit and lower limit.
Reason (R): To draw the frequency polygon without Histogram, we require the class mark.

 
 
 
 

17. If  represents the mean of n observations x1, x2, …, xn, then value of  

 
 
 
 

18. A curious 12th class student wants to know and collect the data regarding the percentage of students who got grade A1 in Mathematics during the last 10 years in Board Examinations.

This collected data is known as

 
 
 
 

19. If the mean of the observations

x, x + 3, x + 5, x + 7, x + 10

is 9, the mean of the last three observations is

 
 
 
 

20. Class mark of the class 70–80 is

 
 
 
 

21. In a given data, some variables are given with particular values, we want to represent these graphically, then we can represent these, using

 
 
 
 

22. Class mark of a particular class is 6.5 and class size is 3, then class interval is

 
 
 
 

23. Given below are the seats won by different political parties in the polling outcome of a state assembly election:

Political party A B C D E F
Seats won 75 55 37 29 10 36

The graphical representation will be

 
 
 
 

24. When in a frequency distribution, class widths are not same and we have to draw histogram then,

 
 
 

25. Direction: In the following questions, a statement of assertion (A) is followed by a statement of reason (R) is given. Choose the correct answer out of the following choices.

Assertion (A): The lower class limit for the class 50-59 is 59.
Reason (R): The least number of the class is called lower class limit.

 
 
 
 

26. In a continuous frequency distribution, class mark of a class is 85 and lower limit is 83, then its upper limit is

 
 
 
 

27. In a grouped frequency data, class intervals are 0–20, 20–40, 40–60, …, then the class width is

 
 
 
 

28. Direction: In the following questions, a statement of assertion (A) is followed by a statement of reason (R) is given. Choose the correct answer out of the following choices.

Assertion (A): The class width for the grouped frequency distribution of the class intervals 15.5– 25.5, 25.5–35.5, 35.5–45.5,… is 10.
Reason (R): Class wdth is same as the class size.

 
 
 
 

29. In a grouped frequency distribution, the class  intervals are 1 – 10, 11 – 20, 21 – 30, ……. . The class width is

 
 
 
 

30. Direction: In the following questions, a statement of assertion (A) is followed by a statement of reason (R) is given. Choose the correct answer out of the following choices.

Assertion (A): The class mark of the classes, 140–150… is 145.
Reason (R): Class mark is the mean value of upper limit and lower limit of classes.

 
 
 
 

31. A frequency polygon can be

 
 
 

32. A student is asked to collect the information about the number of electricity units consumed by a householder in a locality during the last 24 hours, the data thus collected is known as

 
 
 
 

Question 1 of 32