Ace Polynomials with Our Class 10 MCQ Mock Test!

How well do you understand Polynomials? Put your knowledge to the test with our Class 10 Maths Chapter 2 – Polynomials MCQ Mock Test and take your preparation to the next level!

This test is carefully designed to help you master every concept — from zeros of polynomials and their relationship with coefficients to division algorithm and different types of polynomials. Each question pushes your problem-solving skills and analytical thinking — just what you need for your board exams!

What You’ll Get:

  • A collection of high-quality MCQs covering all key topics.
  • Step-by-step explanations to strengthen your conceptual clarity.
  • Instant score analysis to track your progress.
  • Real exam-like experience to boost confidence and speed.

Why Attempt This Test?
Because Polynomials form the foundation for higher algebra and carry significant weight in exams. Practicing with our mock test ensures you understand the logic behind every question, not just the formula.

Attempt the test now and prove your mastery over Polynomials!

1. If the zeroes of the quadratic polynomial ax2 + bx + c, c  0 are equal then

 
 
 
 

2. If one of the zeroes of a quadratic polynomial of the form x2 + ax + b is the negative of the other, then it

 
 
 
 

3. A quadratic polynomial whose one zero is 6 and sum of the zeroes is 0, is

 
 
 
 

4. Zeroes of a polynomial can be determined graphically. No. of zeroes of a polynomial is equal to no. of points where the graph of polynomial

 
 
 
 

5. The zeroes of the polynomial f(x) = x2 – 2x – 16 are

 
 
 
 

6. If the zeroes of the quadratic polynomial x2 + (a + 1) x + b are 2 and –3, then

 
 
 
 

7.

If the sum of the zeroes of the polynomial

P(x) = (p2 – 23)x2 – 2x – 12 is 1, then p takes the value (s)

 
 
 
 

8. The graph of y = x3 – 4x cuts x-axis at (–2, 0), (0, 0) and (2, 0). The zeroes of x3 – 4x are

 
 
 
 

9. If the zeroes of the quadratic polynomial x2 + (a + 1)x + b are 2 and –3, then

 
 
 
 

10.

Graph of the polynomial p(x) = px2 + 4x – 4 is given as above. The value of p is

 
 
 
 

11. If a and b are the zeroes of the quadratic polynomial f(x) = x2 – x – 4, then the value of is

 
 
 
 

12. If sum of zeroes, a + b = –8 and product of zeroes, ab = 6, then a polynomial whose zeroes are and is

 
 
 
 

13. The zeroes of the polynomial (x – 2)2 + 4 is

 
 
 
 

14. A quadratic polynomial whose one zero is 5 and product of zeroes is 0, is

 
 
 
 

15. If a, b are the zeroes of the polynomial x2 + 5x + c, and a – b = 3, then c =

 
 
 
 

16. The value of k such that the quadratic polynomial x2 – (k + 6)x + 2(2k + 1) has sum of the zeroes as half of their product, is

 
 
 
 

17. If one zero of the polynomial f(x) = (k2 + 4) x2 + 13x + 4k is reciprocal of the other, then k is equal to

 
 
 
 

18. Zeroes of p(x) =  are

 
 
 
 

19.

If one of the zeroes of the quadratic polynomial (k – 1)x2 + kx + 1 is –3, then the value of k is

 
 
 
 

20. If one zero of the quadratic polynomial 2x2 – 8x – m is , then the other zero is

 
 
 
 

21. Ravi claims that the polynomial p(x) = mxa + x2b has 4b zeroes. For Ravi’s claim to be correct, which of these must be true?

 
 
 
 

22. Zeroes of a quadratic polynomial are in the ratio  2 : 3 and their sum is 15. The product of zeroes of this polynomial is

 
 
 
 

23. Consider the following statements
(i) x – 2 is a factor of x3 – 3x2 + 4x – 4.
(ii) x + 1 is a factor of 2x3 + 4x + 6.
(iii) x – 1 is a factor of x5 + x4 – x3 + x2 – x + 1
In these statements

 
 
 
 

24. If the zeroes of the quadratic polynomial x2 + (a + 1)x + b are 2 and –3, then

 
 
 
 

25.

The zeroes of the polynomial f(x) = x2 + x –  are

 
 
 
 

26. If the zeroes of the quadratic polynomial x2 + (a + 1)x + b are 4 and –3, then a – b is

 
 
 
 

27. If the graph of a polynomial p(x) cuts the x-axis at 3 points and touches it at the three points, then the number of zeroes of p(x) is/are

 
 
 
 

28. If p(x) = ax2 + bx + c, then  is equal to

 
 
 
 

29. Twice the product of the zeroes of the polynomial 23x2 – 26x + 161 is 14p. The value of p is

 
 
 
 

30. If a, b are the zeroes of the polynomial  f(x) = x2 – p(x + 1) – q, then (a + 1) (b + 1) =

 
 
 
 

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