Master Statistics with Our Class 10 MCQ Mock Test!

Want to strengthen your data-handling and analytical skills? Test your understanding with our Class 10 Maths Chapter 13 – Statistics MCQ Mock Test!

This test covers every important topic — from mean, median, and mode of grouped data to cumulative frequency and graphical representation of data. Each question is designed to boost your accuracy, interpretation skills, and exam confidence.

What You’ll Get:

A collection of concept-based MCQs on all key formulas and methods.
Step-by-step solutions and explanations for each question.
Instant scoring and performance analysis to track your progress.
Practice that improves your data-handling skills, speed, and accuracy.

Why Attempt This Test?
Because Statistics helps you interpret and analyze data — a skill that’s not just crucial for exams, but also in real life. Regular practice ensures you solve every question with clarity and confidence.

Take the test now and master Statistics effortlessly!

1. Mode and mean of a data are 12k and 15k. Median of the data is

12k

14k

15k

16k

2. While computing mean of grouped data, we assume that the frequencies are

evenly distributed over all the classes

centred at the classmarks of the classes

centred at the upper limits of the classes

centred at the lower limits of the classes

3. The median of set of 9 distinct observations is 20.5. If each of the largest 4 observations of the set is increased by 2, then the median of the new set

is increased by 2

is decreased by 2

is two times of the original number

Remains the same as that of the original set.

4. The times, in seconds, taken by 150 atheletes to run a 110 m hurdle race are tabulated below:

Class	Frequency
13.8 – 14.0 14.0 – 14.2 14.2 – 14.4 14.4 – 14.6 14.6 – 14.8 14.8 – 15.0	2 4 5 71 48 20

The number of atheletes who completed the race in less then 14.6 seconds is:

130

5. Choose the correct answer from the given four options : In the formula for finding the mean of grouped data d_i’s are deviation from a of

lower limits of the classes

upper limits of the classes

mid-points of the classes

frequencies of the class marks

6. Mode is the value of the variable which has:

maximum frequency

minimum frequency

mean frequency

middle most frequency

7. In the following questions, a statement of assertion (A) is followed by a statement of reason (R). Choose the correct answer out of the following choices.

Assertion (A): Consider the following frequency distribution

Class Interval	0–4	4–8	8–12	12–16	16–20
Frequency	6	3	5	20	10

The median class is 12–16.

Reason (R): Let n = Then, the class whose cumulative frequency is just lesser than is the median.

Both A and R are true and R is the correct explanation of A.

Both A and R are true but R is not the correct explanation of A.

A is true but R is false.

A is false but R is true.

8. In the following questions, a statement of assertion (A) is followed by a statement of reason (R). Choose the correct answer out of the following choices.

Assertion (A): The arithmetic mean of the following frequency distribution is 25

Class Interval	0–10	10–20	20–30	30–40	40–50
Frequency	5	18	15	16	6

Reason (R): Mean limit + upper limit) of i^th class interval and f_i is its frequency.

Both A and R are true and R is the correct explanation of A.

Both A and R are true but R is not the correct explanation of A.

A is true but R is false.

A is false but R is true.

9. The median from the table is

Value	7	8	9	10	11	12	13
Frequency	2	1	4	5	6	1	3

10.5

10. If mean = (3 median – mode) . k, then the value of k is

1/2

3/2

11. In the formula , for finding the mean of grouped frequency distribution, u_i =

(a)

(b)

(c)

(d)

12. d_i is the deviation of x_i from assumed mean a.
If mean = x + , then x is

class size

number of observations

assumed mean

none of these

13. For the following distribution:

Marks	Number of Students
Below 10 Below 20 Below 30 Below 40 Below 50 Below 60	3 12 27 57 75 80

the modal class is

10 – 20

20 – 30

30 – 40

50 – 60

14. The relationship between mean, median and mode for a moderately skewed distribution is

mode = median – 2 mean

mode = 3 median – 2 mean

mode = 2 median – 3 mean

mode = median – mean

15. Mean of n numbers x₁, x₂, … x_n is m. If x_n is replaced by x, then new mean is

(a)

(b)

(c)

(d)

16. The abscissa of the point of intersection of both types (less than & more than) of cumulative frequency curves help in finding

mean

median

mode

None of these

17. The abscissa of the point of intersection of the less than type and of the more than type cumulative frequency curves of a grouped data gives its

mean

median

mode

all the three above

18. Mean of 100 items is 49. It was discovered that three items which should have been 60, 70, 80 were wrongly read as 40, 20, 50 respectively. The correct mean is

19. A car travels from city A to city B, 120 km apart at an average speed of 50 km/h. It then makes a return trip at an average speed of 60 km/h. It covers another 120 km distance at an average speed of 40 km/h. The average speed over the entire 360 km will be

(a)

(b)

(c)

(d)

20. Cumulative frequency curve is also called

histogram

ogive

bar graph

median

Question 1 of 20